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x^2-13x-2.9=0
a = 1; b = -13; c = -2.9;
Δ = b2-4ac
Δ = -132-4·1·(-2.9)
Δ = 180.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-\sqrt{180.6}}{2*1}=\frac{13-\sqrt{180.6}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+\sqrt{180.6}}{2*1}=\frac{13+\sqrt{180.6}}{2} $
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